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6x^2=25x-9=0
We move all terms to the left:
6x^2-(25x-9)=0
We get rid of parentheses
6x^2-25x+9=0
a = 6; b = -25; c = +9;
Δ = b2-4ac
Δ = -252-4·6·9
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{409}}{2*6}=\frac{25-\sqrt{409}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{409}}{2*6}=\frac{25+\sqrt{409}}{12} $
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